Simply supported in both ends - Point load in center

Table 7SC1 Simply supported in both ends Point load in center
$M (x)$	$= \frac{P \cdot x}{2}$	for: $x < \frac{L}{2}$	Click to make a calculation...
	$= \frac{P \cdot (L - x)}{2}$	for: $x \geq \frac{L}{2}$
$u (x)$	$= \frac{P \cdot L^{3}}{16 \cdot E \cdot I} \cdot [\frac{x}{L} - \frac{4}{3} \cdot {(\frac{x}{L})}^{3}]$	for: $x < \frac{L}{2}$
$M_{M A X}$	$= \frac{P \cdot L}{4}$
$u_{MAX}$	$= \frac{1}{12} \cdot \frac{M_{MAX} \cdot L^{2}}{E \cdot I} = \frac{1}{48} \cdot \frac{P \cdot L^{3}}{E \cdot I}$	at: $x = \frac{L}{2}$
$γ_{A}$	$= \frac{P \cdot L^{2}}{16 \cdot E \cdot I}$
$γ_{B}$	$= \frac{-P \cdot L^{2}}{16 \cdot E \cdot I}$

Table 7SC1Simply supported in both ends Point load in center